博客
关于我
Hat’s Words(字典树)
阅读量:620 次
发布时间:2019-03-13

本文共 2202 字,大约阅读时间需要 7 分钟。

Hat’s Words

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 11314    Accepted Submission(s): 4041

Problem Description
A hat’s word is a word in the dictionary that is the concatenation of exactly two other words in the dictionary.
You are to find all the hat’s words in a dictionary.
 

 

Input
Standard input consists of a number of lowercase words, one per line, in alphabetical order. There will be no more than 50,000 words.
Only one case.
 

 

Output
Your output should contain all the hat’s words, one per line, in alphabetical order.
 

 

Sample Input
aahathathatwordhzieeword
 

 

Sample Output
ahathatword
 
题解:判断单词是否是由两个单词合并得到,加了个val判断是否为一个完整的单词;本来还以为是只与hat结合呐,神经的只减去hat,谁知道,自己想错了。。。是两个单词的结合;
代码:
1 #include
2 #include
3 #include
4 #include
5 #include
6 using namespace std; 7 #define mem(x,y) memset(x,y,sizeof(x)) 8 const int INF=0x3f3f3f3f; 9 const double PI=acos(-1.0);10 const int MAXN=50010;11 int ch[MAXN][30],word[MAXN],val[MAXN];12 char dt[50010][110];13 int sz;14 void initial(){15 sz=1;16 mem(ch[0],0);mem(word,0);mem(val,0);17 }18 void join(char *s){19 int len=strlen(s),k=0,j;20 for(int i=0;i

 

#include
#include
#include
#include
#include
using namespace std;typedef long long LL;#define mem(x,y) memset(x,y,sizeof(x))#define SI(x) scanf("%d",&x)#define PI(x) printf("%d",x)#define P_ printf(" ")const int INF=0x3f3f3f3f;const int MAXN=1000010;//要开的足够大 int ch[MAXN][30];int word[MAXN];char str[50010][110];int val[MAXN]; int sz;int N;char l[110],r[110];void insert(char *s){ int k=0,j; for(int i=0;s[i];i++){ j=s[i]-'a'; if(!ch[k][j]){ mem(ch[sz],0); ch[k][j]=sz++; } k=ch[k][j]; word[k]++; } val[k]=1;}bool find(char *s){ int k=0,j; for(int i=0;s[i];i++){ j=s[i]-'a'; k=ch[k][j]; if(!word[k])return false; } if(val[k]!=1)return false; return true;}int main(){ int tp=0; sz=1; mem(ch[0],0);mem(val,0);mem(word,0); while(~scanf("%s",str[tp]))insert(str[tp++]);// printf("%d\n",tp); for(int i=0;i

  

转载地址:http://aueaz.baihongyu.com/

你可能感兴趣的文章
mysql5.7 for windows_MySQL 5.7 for Windows 解压缩版配置安装
查看>>
MySQL5.7.18主从复制搭建(一主一从)
查看>>
MySQL5.7.19-win64安装启动
查看>>
mysql5.7性能调优my.ini
查看>>
Mysql5.7深入学习 1.MySQL 5.7 中的新增功能
查看>>
Mysql5.7版本单机版my.cnf配置文件
查看>>
mysql5.7的安装和Navicat的安装
查看>>
mysql5.7示例数据库_Linux MySQL5.7多实例数据库配置
查看>>
MySQL8.0.29启动报错Different lower_case_table_names settings for server (‘0‘) and data dictionary (‘1‘)
查看>>
MySQL8修改密码报错ERROR 1819 (HY000): Your password does not satisfy the current policy requirements
查看>>
MySQL8找不到my.ini配置文件以及报sql_mode=only_full_group_by解决方案
查看>>
mysql8的安装与卸载
查看>>
mysqlbinlog报错unknown variable ‘default-character-set=utf8mb4‘
查看>>
mysqldump 导出中文乱码
查看>>
mysqldump备份时忽略某些表
查看>>
mysqldump实现数据备份及灾难恢复
查看>>
mysqlreport分析工具详解
查看>>
MySQL一个表A中多个字段关联了表B的ID,如何关联查询?
查看>>
MYSQL一直显示正在启动
查看>>
MySQL一站到底!华为首发MySQL进阶宝典,基础+优化+源码+架构+实战五飞
查看>>